Java | Leetcode Java题解之第145题二叉树的后序遍历

题目：

题解：

class Solution {
    public List postorderTraversal(TreeNode root) {
        List res = new ArrayList();
        if (root == null) {
            return res;
        }

        TreeNode p1 = root, p2 = null;

        while (p1 != null) {
            p2 = p1.left;
            if (p2 != null) {
                while (p2.right != null && p2.right != p1) {
                    p2 = p2.right;
                }
                if (p2.right == null) {
                    p2.right = p1;
                    p1 = p1.left;
                    continue;
                } else {
                    p2.right = null;
                    addPath(res, p1.left);
                }
            }
            p1 = p1.right;
        }
        addPath(res, root);
        return res;
    }

    public void addPath(List res, TreeNode node) {
        int count = 0;
        while (node != null) {
            ++count;
            res.add(node.val);
            node = node.right;
        }
        int left = res.size() - count, right = res.size() - 1;
        while (left < right) {
            int temp = res.get(left);
            res.set(left, res.get(right));
            res.set(right, temp);
            left++;
            right--;
        }
    }
}