简单的线程池示例

作者 : admin 本文共1445个字,预计阅读时间需要4分钟 发布时间: 2024-06-17 共1人阅读

线程池可以有效地管理和重用线程资源,避免频繁创建和销毁线程带来的开销。以下是一个简单的线程池示例。

cpp
#include 
#include 
#include 
#include 
#include 
#include 
#include 
class ThreadPool {
public:
ThreadPool(size_t numThreads);
~ThreadPool();
void enqueue(std::function<void()> func);
private:
std::vector<std::thread> workers;
std::queue<std::function<void()>> tasks;
std::mutex queueMutex;
std::condition_variable condition;
bool stop;
void worker();
};
ThreadPool::ThreadPool(size_t numThreads) : stop(false) {
for (size_t i = 0; i < numThreads; ++i) {
workers.emplace_back([this] { this->worker(); });
}
}
ThreadPool::~ThreadPool() {
{
std::unique_lock<std::mutex> lock(queueMutex);
stop = true;
}
condition.notify_all();
for (std::thread &worker : workers) {
worker.join();
}
}
void ThreadPool::enqueue(std::function<void()> func) {
{
std::unique_lock<std::mutex> lock(queueMutex);
tasks.push(func);
}
condition.notify_one();
}
void ThreadPool::worker() {
while (true) {
std::function<void()> task;
{
std::unique_lock<std::mutex> lock(queueMutex);
condition.wait(lock, [this] { return this->stop || !this->tasks.empty(); });
if (this->stop && this->tasks.empty()) return;
task = std::move(this->tasks.front());
this->tasks.pop();
}
task();
}
}
// 示例使用
void exampleTask(int n) {
std::cout << "Task " << n << " is being processed by thread " << std::this_thread::get_id() << std::endl;
std::this_thread::sleep_for(std::chrono::seconds(1));
}
int main() {
ThreadPool pool(4); // 创建具有4个线程的线程池
for (int i = 0; i < 10; ++i) {
pool.enqueue([i] { exampleTask(i); });
}`在这里插入代码片`
std::this_thread::sleep_for(std::chrono::seconds(5)); // 保证主线程等待足够长的时间让线程池处理完任务
return 0;
}
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