代码随想录算法训练营DAY32|122.买卖股票的最佳时机II、55. 跳跃游戏、45.跳跃游戏II

作者 : admin 本文共1261个字,预计阅读时间需要4分钟 发布时间: 2024-06-10 共2人阅读

122.买卖股票的最佳时机II

  • 题目链接:122.买卖股票的最佳时机II
class Solution(object):
    def maxProfit(self, prices):
        """
        :type prices: List[int]
        :rtype: int
        """
        max_profit = 0
        profit = 0
        buyin_idx = 0
        
        for i in range(len(prices)):
            print(buyin_idx)
            if prices[i]< prices[buyin_idx]:
                buyin_idx=i
                
            if prices[i]-prices[buyin_idx]>profit and i<len(prices)-1:
                profit=prices[i]-prices[buyin_idx]
            elif prices[i]-prices[buyin_idx]>profit and i==len(prices)-1:
                profit=prices[i]-prices[buyin_idx]
                max_profit+=profit
            else:
                max_profit+=profit
                profit=0
                buyin_idx=i
        
        return max_profit
class Solution(object):
    def maxProfit(self, prices):
        """
        :type prices: List[int]
        :rtype: int
        """
        max_profit = 0
        
        for i in range(1, len(prices)):
            if prices[i]-prices[i-1]>0:
                max_profit+=prices[i]-prices[i-1]

        return max_profit

55.跳跃游戏

  • 题目链接:55.跳跃游戏
  • 注意这里是while i<=cover
class Solution(object):
    def canJump(self, nums):
        """
        :type nums: List[int]
        :rtype: bool
        """
        if len(nums)==1:
            return True

        cover = 0
        i=0
        while i<=cover:
            cover = max(i+nums[i], cover)
            if cover>=len(nums)-1:
                return True
            i+=1
        
        return False

45.跳跃游戏II

  • 题目链接:45.跳跃游戏II
  • step+1的条件(走不下去了再+1)
class Solution(object):
    def jump(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        
        if len(nums)==1:
            return 0

        nextdistance=0
        curdistance=0
        i=0
        step=0

        for i in range(len(nums)):
            nextdistance=max(i+nums[i], nextdistance)
            if curdistance>=len(nums)-1:
                return step
            if i==curdistance:
                curdistance=nextdistance
                step+=1

        return step
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